Multiple Choice. For each question circle the letter corresponding to the best a

Question

Multiple Choice. For each question circle the letter corresponding to the best answer. No explanation required; no partial credit. Each question is worth 4 points.. A charge q = + 2.0 times 10^-10 C is traveling with a velocity v = 3.0 J m/s in a region where there is a magnetic field B = 2.0 k T. The magnetic force on this charge is 1.2 times 10^-9 kN 1.2 times 10^-9 j N -1.2 times 10^-9 jN 1.2 times 10^-9 I N Consider the region of uniform magnetic field shown in the figure. The dotted line shows the path of a charged particle as it travels through this region. The charge on this particle is positive negative The figure shows a circuit in which a conducting bar is sliding with speed v through a uniform magnetic field B. The conducting bar is sliding along parallel conducting rails and a complete circuit is formed. The current induced in the circuit is clockwise counterclockwise According to one of Maxwell's equations, the net magnetic flux through any closedsurface is mu_0 i_enclosed Zero q_enclosed/epsilon_0 - N (d phi/d t) Each of the six conductors shown in the figure carries a current of 1.0 A either into or out of the page. For the clockwise path shown, the value of in units of T m is -3.77 times 10^-6 +2.51 times 10^-6 +3.77 times 10^-6 +6.28 times 10^-6 0

Explanation / Answer

1. F =q ( v x B)

F = (2 x 10^-10) [ (3j) x (2k)]

F = 1.2 x 10^-9 i N

Ans(D)

2. F = q (v x B)

for initial position:

F -> upward

v -> to the right

B-> into the page

hence q is positive

Ans(A)

3. countercklockwise.

4. B. zero

5. Value = u0 Iin { from Ampere's law}

= (4pi x 10^-7) (- 4 + 1) = - 3.77 x 10^-6

Ans(A)

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