Towards Papermill Co-generation Facility 1 objective This term project primarily

Question

Towards Papermill Co-generation Facility 1 objective This term project primarily aims to make the students think out of the box and try to solve a given problem using their existing knowledge/ experience and by exploring the relevant information from books (e.g., use of library and web search. The students will build confidence in solving unknown but relevant problems in the field. The students will improve their teamwork skills. 2 Scope The scope of the project is slightly above the level of usual class-work such as homeworks, exercise and practice problems 3 Background As we know, pulp and paper manufacturing involves a great deal of humidity, which presents a preventive maintenance and corrosion challenge. A paper mill is a factory devoted to making paper from vegetable fibers such as wood pulp, old rags and other ingredients using a Fourdrinier machine or other type of paper machine. The modern paper mill uses large amounts of energy, water, and wood pulp in an efficient and complex series of processes, and control technology to produce a sheet of paper that can be used in diverse ways 3.1 Scenario I Suppose that you were hired by a paper mill as an engineer, which is planning to use some of its waste products as an energy source from excess process steam, it means that the management is looking for installing turbine generators to produce electricity. Assume that the company has the following choices: 1. Three 10MW turbine generators, or 2. One 20MW and one 10MW turbine generator, or 3. A single 30MW turbine generator. As a company's engineer, you were asked to give your opinion/recommendation about the three given choices to build this new electric co-generation facility. Also, the company advised you to consider cost, reliability and efficiency as the most important factors while giving your recom mendation. What will be your choice/recommendation Justify your answer by explaining the advantages and disadvantages of each choice and support your claim

Explanation / Answer

As an Engineer ,inorder to select a generator for the plant, We need to consider few major factors

In this Case Since the load is not specified . let we assume 18 MW load.

here we have 3 alternatives,

Case1: Three 10 MW generators:

Since the load demand is 18 MW, so here we can utilise two 10 MW generators as major sources and the remaining 10 MW generator as power back-up.

Case 2: 20 MW and one 10 MW generator:

Here we may use 20 MW generator as major power supply generator and since we need equal rated generator as back-up source, Here it may not be a wise decision.

Case 3: Single 30 MW power generator:

Eventhough it is looking somewhat reasonable but inorder to have back-up source, this option will be expensive.

Conclusion:

1.From above all cases, Case 1 will be a wise choice . why because inorder to serve 18 MW load we are considering two 10 MW generators, and if any one of generator is under maintenace we may have back-up from the 3rd generator. This kind of flexibility is not feasible with the rest of two cases.

2. To have back-up source of 20 MW and 30 MW in the 2nd and 3rd case we need large generators of capacity 20 MW and 30 MW which makes the system more expensive.

As an electrical engineer recommend three 10 MW generators.

Scenario 2:

Given data:

Three 10 MW turbine generators,

3- phase, 60 Hz, 12.5 MVA, 0.8 pf lag, 4160 Volts,Star- connected,

Armature resistance= 0.03 ohms, Synchronous reactance=1.1 ohms

Characteristic frequency slope of generator1= 5 MW/Hz,

generator2= 5 MW/Hz,

generator3= 6 MW/Hz,

1. Solution:

Adjusted no load frequency of each generator= 61 Hz.

Supply frequency = 60 Hz,

Power supplied by each of 3 generators =?

As we know that regulation is shown by Hz per MW

Here we have two 5 MW per Hz and one 6 MW per Hz.

Now the regulation of Generator1 and Generator2= 1/5= 0.2 Hz per MW and Generator3= 0.1667 Hz per MW.

Since Power(P)= Regulation*(Frequency no load- rated Frequency) *100

P1= (0.2)*(61-60) *100= 0.2 *100 = 20 MW

P2=(0.2)*(61-60)*100= 0.2 *100 = 20 MW

P3= (0.1667)*(61-60)*100=0.1667 *100= 16.677 MW

I am sorry. I am trying to slove this problem, but i was unable to find exact solution with in prescribed time limit. Give me one day chance, i will try to find the solution to this problem.

Some key point we are missing in the problem. Gen1 and two 5 MW per HZ, Gen3 6 MW per Hz. Is it drooping characterisitcs or raising. If it is drooping we need to consider negative sign in the formula.

it should be drooping only. Please give me clarity, i will try to solve it.

Sorry for inconvenience.

Happy chegging.

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