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6. E nzyme kinetics as an approach to understanding mechanism Which of the follo

ID: 199385 • Letter: 6

Question

6. E nzyme kinetics as an approach to understanding mechanism Which of the following Menten kinetics is false? tatements about a plot of Vo vs. [S) for an enzyme that follows Michaclis- A) As [S] increases, the initial velocity of reaction Vo also increases. tvery high [S], the velocity curve becomes a borizontal line that intersects the y-axis at K K. is the [S] at which 14-1/2-s. D) C) The shape of the curve is a hyperbola. E) The y-axis is a rate term with units of pum/min. 7. Enzyme kinetics as an approach to understanding mechanisnm Michaelis and Menten assumed that the overall reaction for an enzyme-catalyzed reaction could be wntten as ki ky ki Using this reaction, the rate of breakdown of the enzyme-substrate complex can be described by the expression: A) k (E] -[ES) C) k [ES]. D) ki [ES] + [ES]. 8. Enzyme kinetics as an approach to understanding mechanism, Pages: 196-199 An enzyme-catalyzed reaction was carried out with the substrate concentration initially a thousand times greater than the Km for that substrate. After 9 minutes, 1% of the substrate had been converted to product, and the amount of product formed in the reaction mixture was 12 umol. If, in a separate experiment, one-third as much enzyme and twice as much substrate had been combined, how long would it take for the same amount (12 mol) of product to be formed A) 1.5 min B) 13.5 min C) 27 min D) 3 min E) 6 min

Explanation / Answer

6.
Option B is correct.
At high [S], the velocity curve becomes horizontal. But, it does not intersect the Y-axis.

7.
Option D is correct.
ES can dissociate into E+P or E+S
So, the rate of dissociation of ES = k1[ES] + k2[ES]

8.
Option D is correct.
Since the substrate concentration is already saturating, it does not matter if we further increase [S].
Since the [E] is reduced to 1/3 of initial concentration, the time required to achieve an equal amount of product formation will also be 1/3rd of the initial time.
= 9/3 = 3 min

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