1.An ideal spring obeys hookes law F=-kx. Mass of 0.50 kg hung vertically from t

Question

1.An ideal spring obeys hookes law F=-kx. Mass of 0.50 kg hung vertically from this spring stretches the spring 0.075m. Force constant for the spring is

A. 0.30N/m
B. 0.66N/m
C. 6.6N/m
D. 33N/m

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2.If two people different masses push each other then what is true?

(A) The velocity is equal
(B) The momentum of the 2 people are equal magnitude
(C) the Kinetic Energy is equal
(D) Less massive has a smaller initial acceleration than more massive
(E) The center of mass of the 2 people system moves in the direction of the less massive

Explanation / Answer

1.F=Kx and K=F/x=0.5N/0.075meter=6.66 N/m 2.(B) The momentum of the 2 people are equal magnitude

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