If a man whose maw is 70 kg starts running from rest over a distance of 5O m, wi

Question

If a man whose maw is 70 kg starts running from rest over a distance of 5O m, with constant acceleration of 2 m/s', then how fast is he running when he has reached 50 m? After the 5O m mark in part (a.), the man collides with an object of mass 100 kg. What is the resultant speed of this collision? The collision from part (b) occurs on a frictionless surface, resulting in a slide of the man and the object together, then off the edge of a steep slope which is 1 5O m long. The object has a coefficient of friction with the surface of the slope of 0.02. If this scenario is occurring on a planet that has half the mass of Earth and three-fourths the radius of Earth, then what is the resultant speed of the man and the object together at the bottom of the slope? How far would a spring compress, located at the bottom of the slope, if its spring constant was 5000 N/m?

Explanation / Answer

a) using newtons 3rd equation
v^2=u^2+2aS
v=(0+2*2*50)^(1/2)
v=14.14 m/s

b)from momentum conservation

v=14.14/(100+70) =.083 m/s

c)

gravity at this planet g'=[(1/2)*(4/3)^2] *g=(8/9)*g

for calculating resultant speed angle of slope will be needing that is not given in question.

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.