A: Consider a pair of identical wire loops of radius R=2.20 cm. Loop 1 is in the

Question

A:
Consider a pair of identical wire loops of radius R=2.20 cm. Loop 1 is in the x-y plane and centered at the origin. Loop 2 is oriented the same as loop 1, but loop 2 is located a distance z=50.6 cm above loop 1 (i.e., along the z-axis). Both loops carry a current I=66.0 mA, which flows clockwise as viewed from above (from the positive-z side of both loops). Calculate the z-component of the net force on loop 2 due to loop 1.

B:
Now suppose that loop 2 is located at (77.00 cm,0,0) but that otherwise everything is the same. Calculate the x-component of the net force on loop 2 due to loop 1.

Explanation / Answer

Lorentz Force equation (F = I*L*B)
F=66*10-3 *50.6*10-2 *10-7 *2(2.2)2 *66*10-1/(50.62+2.22)3/2

=5.16*10-12N

in the next case force is 0 as the magnetic feilds are parallel to each other

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