Prob. 1 In a sample of nitrogen molecules at 20 degrees Celcius, the molecules h

Q: Prob. 1 In a sample of nitrogen molecules at 20 degrees Celcius, the molecules h

Vrms = (3kT/M) So 514 = (3x 1.3806503 × 10-23 x293/M) M = 4.59352758 × 10-26 kg (b) New Vrms = (3 x 1.3806503 × 10-23 x 373 / M) = 336 331.427 m/s

ID: 1986951 • Letter: P

Question

Prob. 1

In a sample of nitrogen molecules at 20 degrees Celcius, the molecules have an rms (root-mean-square) speed of Vrms = 514 m/s.

a.) What is the mass of a nitrogen molecule?

b.) What is the rms speed of the molecules when the temperature is raised to 100 degrees Celcius?

Prob. 2

Given a 50g sample of ice at -5.0 degrees Celcius,

a.) How much heat is required to convert this sample of 50g of ice at 0 degrees Celcius?

b.) How much less heat is required to convert 50g of ice at 0 degrees celcius to 50g of water at 0 degrees Celcius? The specific heat of ice is 2100 J/kgK.

Thnx

Explanation / Answer

Vrms = (3kT/M)

So 514 = (3x 1.3806503 × 10-23 x293/M)

M = 4.59352758 × 10-26 kg

(b) New Vrms = (3 x 1.3806503 × 10-23 x 373 / M) = 336 331.427 m/s

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Prob. 1 In a sample of nitrogen molecules at 20 degrees Celcius, the molecules h

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