A glass windowpane in a home is 0.620 cm thick and has dimensions of 1.06 m 1.60

Question

A glass windowpane in a home is 0.620 cm thick and has dimensions of 1.06 m 1.60 m. On a certain day, the temperature of the interior surface of the glass is 28.0°C and the outdoor temperature is 0°C. Assume the thermal conductivity of the glass is 0.8 W/m · °C.
(a) What is the rate at which energy is transferred by heat through the glass? W

(b) How much energy is transferred through the window in one day, assuming the temperatures on the surfaces remain constant? J

Please show the steps to getting the answer please.

Explanation / Answer

Thickness L = 0.620 cm
                   = 0.0062 m Area A = 1.06 m x 1.60 m               = 1.696 m 2 The temperature of the interior surface of the glass t = 28.0°C The outdoor temperature t '= 0°C The thermal conductivity of the glass K = 0.8 W/m · °C. (a) The rate at which energy is transferred by heat through the glass Q = KA(t-t') / L Substitute values we get Q = 6127.48 watt

(b) Energy is transferred through the window in one day Q ' = Q x 24 8 60 x 60     Since 1 day = 24 x 60 x 60 s                                                                                             = 529.41 x 10 6 J

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