In a game of football outdoors on a cold day, a player will begin to feel exhaus

Question

In a game of football outdoors on a cold day, a player will begin to feel exhausted after using approximately 7.95 105 J of internal energy.
(a) One player, dressed too lightly for the weather, has to leave the game after losing 6.55 105 J of heat. How much work has he done?
(the answer is not 140000J)

(b) Another player, wearing clothes that offer better protection against heat loss, is able to remain in the game long enough to do 2.09 105 J of work. What is the magnitude of the heat that he has lost?
(the answer is not 1004000 J)
Please show the work. thanks!

Explanation / Answer

Player with better protection provides work = 2.09 *10^5 J Change in internal energy = 7.95 * 10^5 J Change in internal energy = work done + heat lost. 7.95 *10^5 = 2.09 *10^5 + heat lost Heat lost = 5.86 *10^5 Joule For the first part. heat lost + work done = Change in internal energy => 6.55 *10^5 + work done = 7.95 *10^5 => work done = 1.4*10^5 J

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