The diagram shows the pressure and volume of an ideal gas during one cycle of an
ID: 1984221 • Letter: T
Question
The diagram shows the pressure and volume of an ideal gas during one cycle of an engine. As the gas proceeds from state 1 to state 2, it is heated at constant pressure. It is then cooled at constant volume, until it reaches state 3. The gas is then cooled at constant pressure to state 4. Finally, the gas is heated at constant volume until it returns to state 1.
= The diagram shows the pressure and volume of an ideal gas during one cycle of an engine. As the gas proceeds from state 1 to state 2, it is heated at constant pressure. It is then cooled at constant volume, until it reaches state 3. The gas is then cooled at constant pressure to state 4. Finally, the gas is heated at constant volume until it returns to state 1.Explanation / Answer
W12= pdv = 3P0(4V0-V0) = 3P03V0= 9P0V0 W23= 0 as there is no change in volume. W34= pdv = P0(V0-4V0) = P0(-3V0)= -3P0V0 W41= 0 as there is no change in volume. Wnet= W12+W23+W34+W41= 9P0V0-3P0V0= 6P0V0 as it is an ideal gas PV=nRT at state 1 3P0V0=nRT1 :. 3K=T1 as P0V0/nR=k where k is any constant at state 3 P04V0=nRT3 :. 4K=T3 as P0V0/nR=k where k is any constant equatin value of K: :. T1/3=T3/4 :. T3= 4T1/3
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