I have an exam tomo morning. how would I go about solving this? Thanks! = Find t

Question

I have an exam tomo morning. how would I go about solving this? Thanks!

    =    Find the currents in the circuit branches in the figure. Express your answers using two decimal places separated by commas. I1, I2, I3, I4, I5, I6 = A I have an exam tomo morning. how would I go about solving this? Thanks!

Explanation / Answer

consider superposition principle assume only V1 is there => V2 is open then i2 = i3 = 0 ; i1 = 20/ (5 + 2/3) = 3.53 A i5=i6=i4 = i1 /3 = 1.176 A ( eac res= 2ohms equal sharing ) now assume only V2 is there => VI is open i'5= i'6= i'4 = 0 i'1 = 10/5+2.4 = 1.35A i'2 = 1.35 (6/10) = .81 A i'3 = 1.35 (4/10) =.54 A hence the actual currents due to the two sources ;I= i + i' I1 = 3.53 + 1.35 = 4.88 A I2 = .81 A I3 = .54A I4 = I5= I6=1.176A

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