I got a)1.42 and b).99 which are both wrong. You drill a hole at the end of a so

Question

I got a)1.42 and b).99 which are both wrong.

You drill a hole at the end of a solid thin rod of length 1 m, and then attach the rod through this hole onto an approximately frictionless pivot. You then release the rod from rest at a reasonably small angle from vertical, so that it executes simple harmonic motion.

a.) What will be its oscillation period?


b.) If the bottom of the rod varies its height above the ground by 1 cm during the oscillation, what was its initial angle from the vertical?
(Note: You may assume the width of the stick is negligible to make this well defined.)

Explanation / Answer

a.) timeperiod =2pvlength/vg=2.006066 seconds where length=1 meter g=9.81m/s^2 b.)bottom varies with 1cm height +> at heighest position the the pivot of the rod is 100-1=99cms from horizontal line at the top. therefore angle of inclination cosf=99/100=0.99 f=8.1096o

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