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Read: 3. The following data were collected during a study of the solute concentr

ID: 197819 • Letter: R

Question

Read: 3. The following data were collected during a study of the solute concentrations on osmosis in a potato Table 1: Recorded Mass(grams) 096 KCI 1% KCI core over a period of 60 minutes 0 minutes 6.2 6.5 6.3 1 1- Te 20 minutes 6.3 6.6 6.1 40 minutes 6.5 6.6 5.8 60 minutes 6.7 6.8 5.6 496 KCI Use the data in Table 1 and the formula for percent change in mass to complete Table 2 a. below. The first two calculations have been done for you as examples Table 2: Cumulative Percent Change in Mass 0% Ka 1% KCI 60 minutes 40 minutes 20 minutes 1.6 0 minutes 4% KCI lass (current time point)- Mass (time point zero) X 100 Cumulative % change- Mass (time point zero 6.3-62 x100-16g x100-1.6g 6.2-6.2 x100-0g For 0% KCI at 20 minutes: 6.2 For 096 KCI at 0 minutes: For 096 KCl at 60 minutes: For 0% KCI at 40 minutes: Complete the calculations for 1% and 4% KCL

Explanation / Answer

Ans a:

Concentration for 0% KCl :

=(6.5-6.2)×100/6.2

=4.838

=4.8g

=(6.7-6.2)×100/6.2

=8.06

=8.0g

calculations for 1% KCl:

= (6.5-6.5)×100/6.5=0g

(6.6-6.5)×100/6.5=1.54g

(6.6-6.5)×100/6.5=1.54g

(6.8-6.5)×100/6.5=4.6g

calculation for 4% Kcl :

(6.3-6.3)×100/6.3=0g

(6.1-6.3)×100/6.3=3.17 or 3.2 g

(5.8-6.3)×100/6.3=-7.9g

(5.6-6.3)×100/6.3=-11.11g

(Minus sign indicates reduction in mass).

From table 2,

ans (b)