a ball with a mass of 0.600 kg is initially at rest. it is struck by a second ba

Question

a ball with a mass of 0.600 kg is initially at rest. it is struck by a second ball having a mass of 0.400 kg, initially moving with a velocity of 0.250 m/s towards the right along the x-axis. after the collision, the 0.400 kg ball has a velocity of 0.200 m/s at an angle of 36.9 degrees above the x axis in the first quadrant. both balls move on a frictionless horizontal surface. (a) what are the magnitude and direction of the velocity of the 0.600 kg ball after the collision? (b) what is the change in total kinetic energy of the two balls as a result of the collision?

Explanation / Answer

A) By conservation of momentum (v_{0.6} = m(v_2-v_1)/(m+M) = 0.0333 m/s) B) Right C) 4.5mJ of 0.4kg ball and 0.333 mJ of 0.6kg ball

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