At time t = 0, a ball is struck at ground level and sent over level ground. The

Question

At time t = 0, a ball is struck at ground level and sent over level ground. The figure below gives the magnitude p of the ball's momentum versus time t during the flight. (p1 = 7.0 kg·m/s and the vertical axis is marked in increments of 2.0 kg·m/s.) At what initial angle above the horizontal is the ball launched?

At time t = 0, a ball is struck at ground level and sent over level ground. The figure below gives the magnitude p of the ball's momentum versus time t during the flight. (p1 = 7.0 kgm/s and the vertical axis is marked in increments of 2.0 kgm/s.) At what initial angle above the horizontal is the ball launched?

Explanation / Answer

When momentum of particle reach minimum, the vetical component of velocity is zero. t˜2,3(s) when p min=p1. P1=v_horizontal *m. while p_maximum=v_initial*m. cos=v_hori/v_ini so cos=p1/p_maximum p1=10 p_max=7+4*2=15. so cos=7/15 ==> = 62.18 degree

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.