2.1 g spider is dangling at the end of a silk thread. You can make the spider bo

Question

2.1 g spider is dangling at the end of a silk thread. You can make the spider bounce up and down on the thread by tapping lightly on his feet with a pencil. You soon discover that you can give the spider the largest amplitude on his little bungee cord if you tap at a frequency of 1.2 Hz. What is the spring constant of the silk thread?

Will I be using the equation, v = sqrt( k/ m) * sqrt (a^2 - x^2)?

Im quite confused here. Since it is in hertz and not seconds. I do understand it reinforces and does not cancel at 1.2Hz

Explanation / Answer

= k/m

f = /2

so 2*1.2 = (k/0.0021)

k = 0.1194 N/m

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