A hockey puck with mass 0.248 kg traveling along the blue line (which is a blue-

Question

A hockey puck with mass 0.248 kg traveling along the blue line (which is a blue-colored line on the ice in a hockey rink) at 1.26 m/s strikes a stationary puck with the same mass. One puck exits the collision in a direction that is 31.1 degrees away from the blue line at a speed of 0.739 m/s. What is the direction and magnitude of the velocity of the second puck after the collision? (Give the direction relative to the positive x-axis.) Is this an elastic collision?
v2= ------- m/s, and (theta) = ----- (degrees)

Explanation / Answer

For elastic collision, both momentum and energy is coserved.            m u1 + 0 = m V1 cos + m V2 cos       .....(1)                 here u is initial and v is final velcoities             0 + 0 = m V1 sin - m V2 sin ......(2) Conservation of energy           (1/2) m u1^2 + 0 = (1/2) m V1^2 + (1/2) m V2^2   ....(3) Solving all the three equation for angle made by the second puck is                  = tan^-1 [ (V1 cos ) / ( u1 - V1 cos ) ]                     = tan^-1 [ (0.739) sin 31.1 / (1.26 - (0.739) cos 31.1 ]                      = 31.3 Speed of the second puck after collision is           V2 = V1 sin 31.1 / sin 31.3                = 0.735m/s                    =

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