Q. A 20 kg wooden ball hangs from a 2.0-m-long wire. The maximum tension of the

Question

Q. A 20 kg wooden ball hangs from a 2.0-m-long wire. The maximum tension of the wire
can withstand without breaking is 400 N. A 1.0 kg projectile, traveling horizontally immediately
before the collision, hits and embeds itself in the wood ball.

1.Could you please show a free body diagram of the wooden ball immediately after the collision?

2. Could you please show which direction the following force act?

(M+m)v²/l where M= 20kg, m=1kg , l= 2m and v is the finial velocity

Tmax = (M+m)g - (M+m)v²

I am confuse yellow highlighted part

Explanation / Answer

mv^2/r=600N m=20 r=1.5 solve for v ..... v=6.71m/s v=(m(proj.) v(proj.)) / (m(proj) + (20)) (6.71m/s)= ((.8) v(proj)) / ((.8) + (20)) v(proj) = 174.4m/s

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