The uniform rod of length 0.60 m, mass 1.0 kg shown below, rotates in the plane

Question

The uniform rod of length 0.60 m, mass 1.0 kg shown below, rotates in the plane of the figure
about an axis through one end, with a rotational inertia of 0.12 kg m2 . As the rod swings
through its lowest position, it collides with a 0.20 kg putty wad that sticks to the end of the rod.
If the rod’s angular speed just before the collision is 2.4 rad/s, what is the angular speed of the
rod-putty system immediately after the collision?
(Neglect air-resistance and any friction in the pivot.)

please no guessing and step by step . thank u very much

Explanation / Answer

by conservation of angular momentum, I1 w2 = I2 w2, where w2 is the final rotational speed of the system. ie., 0.12 x 2.4 = ( 0.12 + 0.2 x 0.36 ) w2 or w2 = 1.5 rad /sec.

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