so in a simple harmonic lab experiment using a pendulum and spring in 2 seperate

Question

so in a simple harmonic lab experiment using a pendulum and spring in 2 seperate experiments we studied the oscillations. we measured T(s) values to find the period for 20 oscillations for each the spring and the pendulum, so we used T= t2-t1 /20, where t1 is always 0 and t2 was the final time after 20 oscillations. If we did this same experiment on the moon where the gravity is 1/6 of the earth, quantitatively how would this have changed our experimental values for each the spring and the pendulum experiment? use numbers not just guesses, how much different or same factor difference?

Explanation / Answer

time peroid Te = 2 (l/g)0.5 on earth

on moon Tm = 2 (l/g/6)0.5

solving we get

Tm = 2.449 Te

so difference = 2.449

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