(a) At what constant speed should the bar move to produce an 8.60 -mA current in

Question

(a) At what constant speed should the bar move to produce an 8.60-mA current in the resistor?
1 m/s

(b) What is the direction of the induced current?

(c) At what rate is energy delivered to the resistor?
3 mW

(d) Explain the origin of the energy being delivered to the resistor.
4

A conducting bar of length i moves to the right on two frictionless rails as shown in the figure below. A uniform magnetic field directed into the page has a magnitude of 0.280 T. Assume R = 8.70 ohm and i = 0.320 m. (a) At what constant speed should the bar move to produce an 8.60-mA current in the resistor? m/s (b) What is the direction of the induced current? clockwise counterclockwise into the page out of the page (c) At what rate is energy delivered to the resistor? mW (d) Explain the origin of the energy being delivered to the resistor.

Explanation / Answer

a)The formula for the induced emf is V = Blv (IR) = Blv So the speed of the bar is v= (IR)/(Bl) = ((8.6 x10^-3A )( 8.70 O))/(( 0.280 T)(0.32 m)) = 0.835 m/s b)The direction of induced current is counter clock wise. c) The rate of energy delivered to the resistor is P = I^2 R = (8.6 x10^-3A )^2(8.70 O) = 0.6435 mW d) Origin of energy being delivered to resistor is from magnetic field

Related Questions

Navigate

• Browse (All)
• Browse #
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.