If forces of 3.0 N North and 6.0 N West are applied to an object, what force (an

Question

If forces of 3.0 N North and 6.0 N West are applied to an object, what force (and direction) is required to keep the object at rest? (6.7 N at 27 degree S of E) Calculate the tension in the two cable supporting the 70. kg load Find the cord tension given that the rod is not moving. Recall that torque depends on the perpendicular force component only. (41N) A student in push up position places a bathroom scale under her hands and another one under her feet. The distance between the scales is 1.25 metres the scale under her toes reads 25.0 kg and the one under her hands reads 22.5 kg. Find her mass (47.5 kg) the distance from her toes to her centre of mass. (59.2 cm)

Explanation / Answer

T=tension of the right rope; T' = tension of the left rope

Tcos(30) = T'cos(40)

Now Tsin30 + T'sin40 = 70*9.8

Tsin30 + Tcos30tan40 = 70

=> T= 560 N

and T' = 630 N

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