2. Use the following kinematics equation to calculate the initial velocity of th

Question

2. Use the following kinematics equation to calculate the initial velocity of the popper based on how long it is in the air:



H = h0 + v0t – ½ gt2


where the final height h = 0 and initial height ho = 0 after the popper travels the total time up and down over your measured time t.

Note: For question 2, use the equation initial velocity = ½ gt - this is how the equation rearranges when the two heights = zero. So, multiple ½ times 9.8 (the value for g) times your average time is seconds from Table 1. Your answer will be in m/sec)

Explanation / Answer

H = h0 + v0t – ½ gt2

comparing it with S=ut+1/2at2
we know that S= h-h0
u=Vo
t=t
a=-g

so we have
0= h0 + v0t – ½ gt2
this is a quadratic in t, with the solutions

t= [Vo +- Vo^2 - 2gho ] / 2g

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