A fireworks rocket is launched vertically (+y-direction) into the night sky with

Question

A fireworks rocket is launched vertically (+y-direction) into the night sky with an initial speed of 45.2 m/s. The rocket coasts after being launched, then explodes and breaks into two pieces of equal mass 2.60 s later.
(a) If each piece follows a trajectory that is initially at 43.7° to the vertical, what was their speed immediately after the explosion?

(b) What is the velocity of the rocket's center of mass before and after the explosion?
(m/s) y-direction

(c) What is the acceleration of the rocket's center of mass before and after the explosion?
(m/s2) y-direction

Explanation / Answer

a ) vcos = 45.2 m/s - 9.8 * 2.60 s

vcos= 19.72 m/s

speed immediately after explosion is, v=19.72 m/s / cos ( 43.7 )

= 27.276 m/s

b ) velocity of rocket's center of mass before and after collission is

v = 19.72 m/s

c ) acceleration is v = u + at

27.276 m/s = 19.72 m/s + a * 2.60 s

acceleration of center of mass for before and after collission is a = 2.91 m/s^2

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.