(Problem 39) There are two genetic loci that cause albinism in humans: gene A an

Question

(Problem 39) There are two genetic loci that cause albinism in humans: gene A and gene B. An individual who is homozygous recessive (aa and/or bb) would exhibit the albino phenotype. Two albinos marry and have four normal children. Which of the following crosses would allow this to be possible?

Question 14 options:

A/a x a/a

A/A x a/a

A/B x a/b

A/b x a/B

A/A b/b x A/A B/B

A/A b/b x a/a B/B

A/A B/B x a/a b/b

A/a x a/a

A/A x a/a

A/B x a/b

A/b x a/B

A/A b/b x A/A B/B

A/A b/b x a/a B/B

A/A B/B x a/a b/b

Explanation / Answer

since both the parents are albinos, they must have a homozygous recessive location available atleast at 1 site in their genome so the answer should be option 6) A/A b/b x a/a B/B

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