From the bottom of the first hill, the roller coaster goes up a second hill. Let

Question

From the bottom of the first hill, the roller coaster goes up a second hill. Let's say that the peak of the second hill is 48.0 m higher than the bottom of the first hill, and that the shape of the second hill is that of a vertical circular arc with radius of 30.0 m.

(c) If resistive forces acting on the coaster cause a loss of 5% of the coaster's mechanical energy as it moves from the bottom of the first hill to the top of the second hill, what is your speed as you pass over the top of the second hill? Notes that, this time, we're looking for the speed in meters per second.

Explanation / Answer

using conservation of energy,

.95mgh = .5*mv^2

so, v= sqrt(1.9gh)
so, v= 29.9 m/s

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