(a) Calculate the wavelength of light in vacuum that has a frequency of 3.4 1011

Question

(a) Calculate the wavelength of light in vacuum that has a frequency of 3.4 1011 Hz.
______m

(b) What is its wavelength in carbon disulfide? (The index of refraction of carbon disulfide is 1.628.)
_____m

(c) Calculate the energy of one photon of such light in vacuum. Express the answer in electron volts.
_____eV

(d) What is the properties of and effect on the energy of the photon when it enters the carbon disulfide? (Select all that apply.)
__the energy does not change
__the energy is inversely proportional to the frequency
__the energy goes down
__the energy goes up
__the energy is proportional to the frequency
__the energy is not proportional to the frequency

Explanation / Answer

a) wavelength=c/f =0.882*10pow(-3) m b) wavelength=0.882*10pow(-3) /1.628 =0.542*10pow(-3)m c) E=h*f = 1.4*10pow(-3)ev d)energy does not change and is proportional to frequency.

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