Hello guys. Am asking this for the third time. i didn\'t get any helpful answer

Question

Hello guys.

Am asking this for the third time. i didn't get any helpful answer in the first two answers , one of them was my bad , it was not clear, the other one i couldnt read his font at all. SO PLEASE , if u want to help , am thankful , and please write it neatly in here. if you want to solve it on a paper , i dont mind too , but PLEASE , take a clear picture of it ! thank you so much !!

so we have 3 blocks , W , W1 and W2 . their masses are 100 N , 500 N and 250 N respectively. y is given to be 0.4 m, and l is giving to be 1 m . what is Xeq ?

Thank you

Explanation / Answer

balancing force on middle block,W  along horizontal direction

 (1- Xeq)/Xeq  = W1/W2

we can see that Xeq =  (W2/W1) * (1 - Xeq)

                 = solving for Xeq = 1/3 m

see : this problem is solved anaytically. you can see that as increasing  W1 , Xeq will be getting shorter and this will be proportional to weight ratio.

 now let W2 = 0    block will totally slide towrds W1, so Xeq = 0

as , Xeq * W1  = (1- Xeq) * W2

for W2 = 0  -----> Xeq

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