Figure 1.55 shows the trajectory of a ball traveling through the air, affected b

Question

Figure 1.55 shows the trajectory of a ball traveling through the air, affected by both gravity and air resistance. Hence are the positions of the ball at several successive times: What is the average velocity of the ball as it travels between location A and location B? If the ball continued to travel at the same average velocity during the next second, where would it be at the end of that second? ( That is, where would it be at time t = 2 seconds? ) How does your prediction from part ( b ) compare to the actual position of the ball at t = 2 seconds ( location C ) ? If the predicted and observed locations of the ball are different, explain why.

Explanation / Answer

suppose the ball reaches a point (x,y,z) by traveling with the same average velocity , then
the average velocity can be written as
= ( <x,y,z> - < 22.3 , 26.1 , 0>) /(2-1)
As the average velocity is same , implies
< x-22.3 , y -26.1 , z > = < 22.3 , 26.1 , 0>

=> x -22.3 =22.3 = > x =44.6
=> y-26.1 = 26.1 => y = 52.2
=> z -0 =0 => z =0

<x,y,z > = <44.6 , 52.2 , 0> m

Related Questions

Navigate

• Browse (All)
• Browse F
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.