The quantitative analysis for reduced glutathione in blood is complicated by the
ID: 196612 • Letter: T
Question
The quantitative analysis for reduced glutathione in blood is complicated by the presence of many potential interferents. In one study, when analyzing a solution of 10-ppb glutathione and 1.5-ppb ascorbic acid, the signal was 5.43 times greater than that obtained for the analysis of 10-ppb glutathione. What is the selectivity coefficient for this analysis? The same study found that when analyzing a solution of 350-ppb methionine and 10-ppb glutathione the signal was 0 906 times less than that obtained for the analysis for the analysis of 10 pbb glutathione. what is the selectivity coeefficient for this analysis? in what way do these interferents behave differently?
Explanation / Answer
The formula is =
Ssamp = SA +SI
Here S is selectivity, samp abbreviate for sample, A abbreviate for Analyte and I for interfering speices.
By exploring the above formula we get-
Ssamp = kA nA + kI nI
Here k and n are interferent’s sensitivity moles respectively.
Here in the question, the analyte is 10-ppb glutathione and interferent is ascorbic acid.
To find interferent’s sensitivity of glutathione we will use following formula-
kG= SG / CG
here k is the glutathione sensitivity, S is the selective concentration of glutathione and C is the absolute.
The selective concentration is 10ppb and absolute concentration is also 10 ppb
So the glutathione sensitivity kG = 10/10 =1
We have given that in solution of 10-ppb glutathione and 1.5-ppb ascorbic acid the signal was 5.93 times more.
Therefore the obtained result of selectivity would be
[(Obtained result- 10) / 100] x100= +5.93
Obtained result =10+ 5.93
Obtained result =15.93
Putting the values in the formula
Ssamp = kA nA + kI nI
Ssamp = kG nG + kAs nAs [As = ascorbic acid]
15.93 = 1 x 10 + kAs x1 [to make calculation easy we take ascorbic acid sensitivity as 1]
Now kAs = 5.93
Now the solution’s selection coefficient CGCAs
= kAs / kG
= 5.93/ 1
=5.93
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