A 25.0 kg sled is at rest at the top of a straight, snow-covered hill which has

Question

A 25.0 kg sled is at rest at the top of a straight, snow-covered hill which has a length of 40.0 m (measured along the
hill). The hill is inclined at 20.0 degrees with respect to the horizontal. The coefficient of kinetic friction between the sled and
the hill is 0.100.

What is the minimum possible value of the coefficient of static friction
between the sled and the hill? Then, if the sled is given a kick, it will begin sliding down the hill. What is the magnitude of the sled's acceleration
down the hill?

Explanation / Answer

Ff=Fg; Fg=mgcos and Ff=mgsin so sin=cos so =tan20.363. If is smaller the sled will slide.

For the magnitude of acceleration then Fnet=mgcos-mgsin and F=ma so a=mg(cos-sin)/(m) so a=9.8(cos20-.1sin20) so a=8.87m/s^2

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