The helicopter view in the figure below shows two people pulling on a stubborn m
ID: 1963288 • Letter: T
Question
The helicopter view in the figure below shows two people pulling on a stubborn mule. (Take F1 = 112 N and F2 = 72.0 N.)
(a) Find the single force that is equivalent to the two forces shown above.
(b) Find the force that a third person would have to exert on the mule to make the net force equal to zero.
I have saw this question on here but all the steps i have follwed and swapped numbers have been incorrect when i entered them online.
magnitude N direction ° (counter-clockwise from the +x-axis)Explanation / Answer
Given that F1 = 112 N F2 = 72 N (a) Net force along the Y axis, Fy = F1 sin60 j + F2 sin75 j = 96.99 j + 69.54 j = 166.536 j N Net force along the X axis, Fx = - F2 cos75 i + F1 cos60 i = - 18.63 i + 56 i = 37.37 i N Resultant force F = Fx + Fy = 37.37 i + 166.536 j N Magnitude : Sqrt[(37.37)^2 + (166.536)^2] = Sqrt[ 1396.5169 + 27734.239296] = 170.67 N Direction : Tan^-1[166.536/37.37] = 77.350 counter clockwise from the +ve X axis. (b) The force that a third person would have to exert on the mule to make the net force equal to zero is - 37.37 i - 166.536 j Magnitude : Sqrt[(37.37)^2 + (166.536)^2] = Sqrt[ 1396.5169 + 27734.239296] = 170.67 N Direction : Tan^-1[166.536/37.37] = 77.350 + 1800 = 257.350 counter clockwise from the +ve X axis.
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