A student decides to move a box of books into her dormitory room by pulling on a

Question

A student decides to move a box of books into her dormitory room by pulling on a rope attached to the box. She pulls with a force of 148 N at an angle of 30.0° above the horizontal. The box has a mass of 20.0 kg, and the coefficient of kinetic friction between box and floor is 0.300.

The student now starts moving the box up a 10.0° incline, keeping her 148 N force directed at 30.0° above the line of the incline. If the coefficient of friction is unchanged, what is the new acceleration of the box?

Explanation / Answer

normal force from the incline=(m*g*cos10)-148*sin30 =123N friction force=F=.3*N =.3*123=36.9 so net force in direction of motion=148*cos30-m*g*sin10-F =128.17-38.2-36.9 =53.07 so accelaration=53.07/20=2.6535m/s^2 hope this will help u...

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