initial speed 14m/s, ang 40 deg in x-y plane. g=9.81 a) find intial V y and V x
ID: 1960297 • Letter: I
Question
initial speed 14m/s, ang 40 deg in x-y plane. g=9.81
a) find intial Vy and Vx
b) find a(t), V(t), r(t)
c) max height time, tmax
d) total travel time, tr
Explanation / Answer
a)resolve the velocity in two components along horizontal and perpendicular directions ==>Vy =Vsina=14 sin40=8.999 m/s=9 m/s (approximately) and Vx=Vcosa=14cos40=10.72 m/s b)a(t)= acceleration due to gravity only because no force is acting in the horizontal direction==> a(t)=g=9.81 m/s^2 (downwards)=constant V(t)=[(9-9.8t))^2+10.72^2]^0.5 r(t)=range of projectile=(horizontal component of velocity)*(time) ==>r(t)=Vcosa*t=10.72 *t c)max height time =time of ascent=Vsina/g=9/9.81=0.917 s=time maximum max height=(Vsina)^2/(2*g)=9^2/(2*9.81)=4.128 m time of flight=2*Vsina/g=2*9/9.81=1.834 s d) time of flight=2*Vsina/g=2*9/9.81=1.834 s
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