\"Flux and Conducting Shells\" - A charged particle is in the center of TWO cond

Question

"Flux and Conducting Shells"
- A charged particle is in the center of TWO conductingshells.

If they give you the NET FLUX graph as you move along theradius...how can I use Gauss's law to help figure out the chargesof the particle and the two conducting shells

Explanation / Answer

Find the charge of center particle by Gaussian Surface (GS)inside shell A and around particle. qenc/E0 = -9 *10^5Nm2/C --->charge of particle = -7.97 * 10^6 Then, GS inside shell B, around shell A. qenc/E0 = 4 *10^5 ---> qenc = 3.54 *10^-6 but this is the charge of particle and shell A, you know thecharge of particle so subtract it shell A charge = 3.54 *10^-6 - - 7.97*10^-6= 1.15*10^-5 Then, GS outside both shells, find qenc/E0 = -2 *10^5,subtract shell A and particle from this and get shell B's charge,-5.31*10^-6

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