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A quarterback claims that he can throw the football a horizontal distance of 183

ID: 1953683 • Letter: A

Question

A quarterback claims that he can throw the football a horizontal distance of 183 m (200 yd). Furthermore, he claims that he can do this by launching the ball at the relatively low angle of 35° above the horizontal. To evaluate his claim, determine the speed with which this quarterback must throw the ball. Assume that the ball is launched and caught at the same vertical level and that air resistance can be ignored. For comparison, a baseball pitcher who can accurately throw a fastball at 45 m/s (100 mph) would be considered exceptional.

Explanation / Answer

given all these, use Kinematic Range Equation, then R = 183 m g = acceleration due to gravity = 9.8 m/s² ? = 35 deg The Range Equation is R = v²sin(2?)/g, or v = v[Rg/sin(2?)]. Then, when you plug in nmbers, you get v = v[(183 m)(9.8 m/s^2)/sin(70) = 43.7 m/s.

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