and the conservation of energy to find the power absorbed by each element. Pleas

Question

and the conservation of energy to find the power absorbed by each element.

Please explain step by step, I've made a mistake somewhere because all of the elements at the end when I look at each one of their [p=vi] don't sum up to zero. Please explain step by step. Canteev if you help me again I when I did the KCL at the upper left node I got I_x + I_y = 0. And when I did the upper right node i got -I_y - I_z = 0. But these didn't add up correctly when i multiplied them by the voltage, so I made a mistake somewhere.

Explanation / Answer

For the voltages, I will choose voltage drop to be positive. Voltage rise: negative current entering: negative current leaving positive KVL : clockwise Vz + Vx - Vy = 0 Vz - 2 + 6 = 0 Vz = -4 V KCL at upper left node: Ix + Iy = 0 Iy = -1 Right upper node: -Iy - Iz = 0 Iz = -Iy = 1 In summary: Vx = -2 V, Vy = -6 V, Vz = -4 V Ix = 1 A, Iy = -1 A, Iz = 1 A Using passive sign convention: Element X: P = -IxVx = -(1)(-2) = 2 W X is absorbing power Element Y: P = -(Iy)(Vy) = -(-1)(-6) = -6 W Y is delivering power Element Z: P = -(Iz)(Vz) = -(1)(-4) = 4 W Z is absorbing power. If you add all the power: 4 + 2 - 6 = 0 Notes: You screwed up on the passive sign convention for power. For element Y, Iy is entering the negative terminal: P = -(V)(I) = -(-6)(-1) = -6 W You also messed up for element Z. All power calculations needed a negative sign in front. Everything else was correct.

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