The population of mosquitoes in a certain area increases at a rate proportional
ID: 1948605 • Letter: T
Question
The population of mosquitoes in a certain area increases at a rate proportional to the current population, and in the absence of other factors, the population doubles each week. There are 500000 mosquitoes in the area initially, and predators (birds, bats, and so forth) eat 60000 mosquitoes/day. Determine the population of mosquitoes in the area at any time. P (t) = 500000ein2 / 7t - 420000 / In2(ein2 / 7 t-1) P(t) = 500000ein2 / 7t-60000/In2(ein2 / 7t-1) P(t) = 500000eln2.t - 420000/in2(ein2.t - 1) P(t) = 500000e7t - 420000(e7t - 1) P(t) = 60000ein2 / 7t - 420000 / In2(ein2 / 7 - 1)Explanation / Answer
C
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