A mixture of gases \"a\" and \"b\" enters a turbine separator at 80 degree F and

Question

A mixture of gases "a" and "b" enters a turbine separator at 80 degree F and 20 psi a. At one exit, 1 mole/hr of gas "a" leaves at 5 psi a and 80 degree F while at the other exit 3 moles/hr of gas "b" leaves at 5 psi a and 40 degree F. The heat interaction rate to the device from the 80 degree F surroundings has a magnitude of 160 Btu/hr and steady state conditions prevail. The molecular weight, specific heat and particular gas constant for gases "a" and "b" are as follows: Gas "a" Gas "b" Ma = 20 lbm/mole Mb = 30 Cpa = .25 Btu/lbm degree R Cpb =. 40 Ra = 76.6 ft lbf/Lbm degree R Rb = 51.4 Calculate the inlet mass flow rate.

Explanation / Answer

Consevation of mass at steady state mass in = mass out mass in = 1x20 + 3x30 mass in = 110 lbm/gr

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