The state 1 h1 (corresponding to given pressure and temp fr. Steam table) = 3424

Question

The state 1 h1 (corresponding to given pressure and temp fr. Steam table) = 3424.6kJ/kg and s1 = 6.1858kJ/kg.k State 2 : h2 = h1-(h1-h2s)ht1 = 3082.6kj/kg and s2 = 6.2781kj/kg-k State 3 : h3 = 3545.3 kj/kg s3 = 6.9072 Kj/kg-k State 4 : h4 = h3 -(h3-h4s)nt2 = 3029.7kj/kg ,s4 = 7.0771 kj/kg-k State 5 : using xs = 0.9747 h5s = 2637.3kj/kg so hs=h4-(h4-h5s)nt3 = 2695.6kj/kg ,s5 = 7.2284kj/kg-k State 6: x6s = 0.0589 h6s =2226.5 kj/kg 'h6 =h5-(hs-h6s)nt4 = 2296.9 kj/kg State 7: at saturated lig h7 = 151.53kj/kg State 8: h8 = h7 + y7(P8-P7) = 151.67 kJ/kg State 9: h9 = 4.6711kJ/kg State 10: h10 = h9+ y9(P10-P9) = 500.64 kj/kg State 11: h11( using Tsat) so h11 = 781.7kJ/kg State 12: sat liq h12 = 762.81kj/kg State 13: Throttling process h13 = h12 = 762.81 kj/kg State 14: sat. condition h14 = 1303.8kj/kg

Explanation / Answer

You need to multiply everything by 0.44216.

State 1: h1 = 1514.22 BTU/lb

s1 = 2.7351 BTU/lb*K

State 2: h2 = 1363 BTU/lb

s2 = 2.7759 BTU/lb*K

State 3: h3 = 1567.59 BTU/lb

s3 = 3.0541 BTU/lb*K

State 4: h4 = 1339.6 BTU/lb

s4 = 3.1292 BTU/lb*K

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