Voltage Division: For the circuit shown in figure 1 assume R1 = 10 k ohm, R2 = 2

Question

Voltage Division: For the circuit shown in figure 1 assume R1 = 10 k ohm, R2 = 20 k ohm . Ignore the load resistor (Rl) for parts (a) and (b). Use voltage division to find V1 and V2. Use the circuit shown directly below. Use the circuit shown directly below for this part. Using KVL, write voltage V in terms of voltages V1/ V2 and show that the voltages found in part (a) satisfy this relationship. Loading: For the circuit shown in figure 1 assume R1 = 10 k ohm, R2 = 10 k ohm and Rl = I00 k ohm. Find the voltage V2 with and without the load resistor Rl. Now, find the voltage V2 if Rl = 1 M ohm. Describe the effect of load resistance on the voltage V2.

Explanation / Answer

a>I=V/R1+R2 =10/30*10^3=3.33*10^-4 V1=I*R1=3.33*10^-4*10*10^3=3.33 V2=I*R2=3.33*10^-4*20*10^3=6.66 b>using KVL V=V1+V2 here V1 and V2 found out satisfy it. as 3.33+6.66=10 c>RL=100*10^3 let current through R2 is I1 and through RL is I2 applying KVL in first loop (I1+I2)*R1+I1*R2=10 applying KVL in outer loop containing RL (I1+I2)*R1+I2*Rl=10 solving I1=4.76*10^-4 I2=4.76*10^-5 V2=I1*R2=4.76*10^-4*10*10^3=4.76 v if RL =10^6 again calculating I1=4.97*10^-4 I2=4.97*10^-5 V2=I1*R2=4.97*10^-4*10*10^3=4.97 v as RL increases V2 increases

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