For the network in circuit 2, the mathematical expression for the current flows

Question

For the network in circuit 2, the mathematical expression for the current flows through the capacitor after the switch is moved to position 1 in time equals to 0 sec is: Given: R1 = 100 ohms R2 = 300 ohms R3 = 200 ohms V = 60 V 200mA(e^(-t/150ms)) 100mA(e^(-t/150ms)) 15 0 mA(e^(-t/300ms)) 100mA(e^(-t/250ms)) 50mA(e^(-t/120ms)) 20mA(e^(-t/10ms)) if the switch is moved to position 1 at time equals to 0 sec. and then moved to position 2 at time equals to sec, the approximate time required for the voltage across the capacitor, vc, to reach 48 V: 241 ms 130 ms 460 ms 89 ms 360 ms 670 ms

Explanation / Answer

option 3 and 2 respectively

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