1) Given that there are just two alleles, A and B for a particular trait and tha
ID: 192996 • Letter: 1
Question
1) Given that there are just two alleles, A and B for a particular trait and that the gene frequency for A is 0.8 in a certain population, what would be the equilibrium frequency of heterozygotes if all the Hardy- Weinberg assumptions were met? Show all work1) Given that there are just two alleles, A and B for a particular trait and that the gene frequency for A is 0.8 in a certain population, what would be the equilibrium frequency of heterozygotes if all the Hardy- Weinberg assumptions were met? Show all work
Explanation / Answer
If there are just 2 alleles, A and B for a particular trait and conditions for Hardy-Weinberg equilibrium are met, then the frequency of the traits will be calculated according to the following formula :
p+q = 1, or p2 + q2 + 2pq = 1
where,
As given in the question, frquency of allele A = 0.8, i.e., p=0.8
Therefore, frequency of allele B will be equal to q, i.e., 1-p = 1-0.8 = 0.2
Hence frequency of heterozygotes if the equillibrium conditions for Hardy-Weinberg equilibrium are satisfied will be equal to 2pq = 2 x 0.8 x 0.2 = 0.32
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