This problem doesn\'t seem to be included for some reason. I keep trying it, but

Question

This problem doesn't seem to be included for some reason. I keep trying it, but i get something completely different even though it seems like a straight forward problem. You can see the answer included in the picture.

Explanation / Answer

There are two loops in the given circuit, applying kvl in the first loop, 12cos(4t)=2i1+8(i1-i2) applying kvl in the second loop.. 2di2/dt+8(i2-i1)=0 =>8(i1-i2)=2di2/dt =>i1=(1/8)[2di2/dt+i2] substituting this value in first equation.. di2/dt+0.1i2=4.8cos(4t) i2=c1exp(-0.1t)-0.03cos(4t)-1.2sin(4t) at t=o,c1=0.03 i2=0.03exp(-0.1t)-0.03cos(4t)-1.2sin(4t) i1 can be found out.. So i(t)=i1+i2=0.033exp(-0.1t)-2.55sin(4t) the power developed is given by P=i(t)[12cos(4t)

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