Problem 1 The force F ={590 i +265 j ?610 k }N acts at the end of the beam. (Fig
ID: 1920984 • Letter: P
Question
Problem 1
The force F={590i+265j?610k}N acts at the end of the beam. (Figure 1)
Part A
Determine the moment of the force about point A.
Express your answers using three significant figures separated by commas.
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Problem 1
The force F={590i+265j?610k}N acts at the end of the beam. (Figure 1)
Part A
Determine the moment of the force about point A.
Express your answers using three significant figures separated by commas.
(MA)x, (MA)y, (MA)z = N?mSubmitMy AnswersGive Up
Provide Feedback
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Problem 1 The force F={590i+265j?610k}N acts at the end of the beam. (Figure 1) Part A Determine the moment of the force about point A. Express your answers using three significant figures separated by commas. (MA)x, (MA)y, (MA)z = N?m SubmitMy AnswersGive Up Provide FeedbackExplanation / Answer
moment = cross product of distance and Force vector
Now, coordinates of point A = 0i + 0j + 0.4k
coordinates of point B = 0.2i + 1.2j + 0.4k
thus, vector ,r = coordinates of point B - coordinates of point A = 0.2i + 1.2j + 0k
thus, moment = rxF = (0.2i + 1.2j + 0k)x(590i+265j?610k) = -732i + 122j - 655k
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