Two cars, A and B, travel in a straight line. The distance of A from the startin

Question

Two cars, A and B, travel in a straight line. The distance of A from the starting point is given as a function of time by xA (t) = alpha t + betat2, with alpha = 2.60 m/s and beta = 1.20 m/s2. The distance of B from the starting point is xB (t) = gammat2 - Delta t3, with gamma = 2 80 m/s2 and Delta = 0.20 m/s3. Which car is ahead just after they leave the starting point? car A car B At what time(s) are the cars at the same point? Express your answer numerically. If there is more than one answer, enter each answer separated by a commas. At what time(s) is the distance from A to B neither increasing nor decreasing? Express your answer numerically. If there is more than one answer, enter each answer separated by a comma. At what time(s) do A and B have the same acceleration? Express your answer numerically. If there is more than one answer, enter each answer separated by a comma.

Explanation / Answer

let y = xb - xa = 2.8*t^2 - .2*t^3 - 2.6*t - 1.2 t^2 we want to find t so that dy/dt = 0 dy/dt = 5.6 t - .6 t^2 -2.6 -2.4*t = 0 t=1 or 13/3

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