https://www.smartphysics.com/Content/Media/UserData/e117983f-9844-68d7-6272-f29a

Question

https://www.smartphysics.com/Content/Media/UserData/e117983f-9844-68d7-6272-f29a1ae11f02/box-in-field.jpg

A empty cardboard box is placed in an electric field pointing upwards with a strength of 1100.0 N/C as shown above. The bottom of the box is tilted up by an angle ? = 20.0o from the horizontal. Side A of the box faces out of the page and is 10.0 cm high and 14.0 cm long. Sides B and C are 10.0 cm high and 11.0 cm deep. Sides D and E are 14.0 cm long and 11.0 cm deep.

2) What is the flux through side B of the box? ?B = N m2C

3) What is the flux through side C of the box? ?C = N m2C

4) What is the flux through side D of the box? ?D = N m2C

5) What is the flux through side E of the box? ?E = N m2C

6) What is the total flux through all six sides of the box? ?Total = N m2C

Explanation / Answer

2)Area of side B=0.1*0.11=0.011

Flux=EASin=4.138Nm2/C

3)Area of side C=0.1*0.11=0.011

Flux=-EASin=-4.138Nm2/C

4)Area of side D=0.14*0.11=0.0154

Flux=-EACos=-15.92Nm2/C

5)Area of side D=0.14*0.11=0.0154

Flux=EACos=15.92Nm2/C

6)the total flux through all six sides of the box=Nm2/C

Related Questions

Navigate

• Browse (All)
• Browse H
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.