cars a and b move in the same direction in adjacent lanes. the position x of car

Question

cars a and b move in the same direction in adjacent lanes. the position x of car a is given in fig. 2-27, from time t=0 to t=7. the figure's vertical scalins is set by xs=32 m. at t=0, car b is at x=0, with a velocity of 12 m/s and a negative constant acceleration aB. What must aB be such that the cars are momentarily side by side (momentarily as the same value of x) at t=4 sec? For that value of aB, how many times are the cars side by side? How many times will the cars be side by side if the magnitude of acceleration aB is more than and less than the answer to the first question?

Explanation / Answer

from the graph the velocity of a is a=tanß=4/2
after 2 second a is on 24 so b must be 24
24=1/2aB4+22.2=====>aB= 0

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