One billiard ball is shot east at 3.5 m/s. A second, identical billiard ball is

Question

One billiard ball is shot east at 3.5 m/s. A second, identical billiard ball is shot west at 2.1 m/s. The balls have a glancing collision, not a head on collision, deflecting the second ball by 90 degrees and sending it north at 1.8 m/s. a. Find the final speed of the first ball. b. Find the direction of the first ball after the collision (angle below the West-East line.)

Explanation / Answer

We generally do not answer the questions of those who are having low rating. You are having a rating of "90%". Please rate all answers and improve your rating. Even if you find the answers are incorrect, first rate Lifesaver or helpful to the best answer and then rate other answers as not helpful. But do rate them for the good of both of us. Thanks!! Coming to the problem u1 = 3.5 i m/s u2 = -2.1 i m/s m1 = m2 = m v2 = 1.8 j Momentum is conserved: 3.5m i - 2.1m i = 1.8m j + v1*m =>v1 = 1.4i - 1.8j a)speed = sqrt((1.4^2)+(1.8^2)) = 2.280 m/s b)Direction = degrees(atan(1.8/1.4)) = 52.125 degrees clockwise from east direction.

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