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https://www.smartphysics.com/Content/Media/UserData/ebfae213-ad62-da58-2e01-ff6f3e3c551b/PV.jpg A heat engine has the three step cycle shown above. Starting from point A, 0.5 L (liter) of monatomic ideal gas expands in the isobaric (constant pressure) process A to B at P = 2.0 atm. B to C is isovolumetric process at V = 5.0 L, and C to A is an isothermal (constant temperature) compression at 300.0 K. 3) If the net work done by the engine per cycle is 676.4 J, find the work done by the gas during process C to A. WCA =__________ J

Explanation / Answer

firstly we find pressure at C,

pAvA=pCvC

pC=1/5 atm............

now WAB=PdV= 2x4.5= 9 latm= 9x101 j=909 j......... (1latm= 101 j)

WBC= 0 as dV=0............

now net work done = WAB + WBC + WAC= 676.4 J

WAC= 676.4-909 J= -232.6 J...............

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